In the figure, UVX and ZYlW are straight lines. ∠UZY = 50°, ∠ZUY = 43°, ∠VWX = 28° and ∠VXW = 120°. Find
- ∠UYV
- ∠YUV
(a)
∠UYZ
= 180° - 43° - 50°
= 87° (Angles sum of triangle)
∠UYV
= 180° - 87°
= 93° (Angles on a straight line)
(b)
∠XVW
= 180° - 120° - 28°
= 32° (Angles sum of triangle)
∠UVY = ∠XVW = 32° (Vertically opposite angles)
∠YUV
= 180° - 93° - 32°
= 55° (Angles sum of triangle)
Answer(s): (a) 93°; (b) 55°
