In the figure, EFH and KJlG are straight lines. ∠EKJ = 42°, ∠KEJ = 49°, ∠FGH = 32° and ∠FHG = 108°. Find
- ∠EJF
- ∠JEF
(a)
∠EJK
= 180° - 49° - 42°
= 89° (Angles sum of triangle)
∠EJF
= 180° - 89°
= 91° (Angles on a straight line)
(b)
∠HFG
= 180° - 108° - 32°
= 40° (Angles sum of triangle)
∠EFJ = ∠HFG = 40° (Vertically opposite angles)
∠JEF
= 180° - 91° - 40°
= 49° (Angles sum of triangle)
Answer(s): (a) 91°; (b) 49°