In the figure, PQS and UTlR are straight lines. ∠PUT = 45°, ∠UPT = 44°, ∠QRS = 38° and ∠QSR = 117°. Find
- ∠PTQ
- ∠TPQ
(a)
∠PTU
= 180° - 44° - 45°
= 91° (Angles sum of triangle)
∠PTQ
= 180° - 91°
= 89° (Angles on a straight line)
(b)
∠SQR
= 180° - 117° - 38°
= 25° (Angles sum of triangle)
∠PQT = ∠SQR = 25° (Vertically opposite angles)
∠TPQ
= 180° - 89° - 25°
= 66° (Angles sum of triangle)
Answer(s): (a) 89°; (b) 66°
