In the figure, PQS and UTlR are straight lines. ∠PUT = 41°, ∠UPT = 40°, ∠QRS = 26° and ∠QSR = 106°. Find
- ∠PTQ
- ∠TPQ
(a)
∠PTU
= 180° - 40° - 41°
= 99° (Angles sum of triangle)
∠PTQ
= 180° - 99°
= 81° (Angles on a straight line)
(b)
∠SQR
= 180° - 106° - 26°
= 48° (Angles sum of triangle)
∠PQT = ∠SQR = 48° (Vertically opposite angles)
∠TPQ
= 180° - 81° - 48°
= 51° (Angles sum of triangle)
Answer(s): (a) 81°; (b) 51°
