In the figure, CDF and HGlE are straight lines. ∠CHG = 47°, ∠HCG = 41°, ∠DEF = 32° and ∠DFE = 111°. Find
- ∠CGD
- ∠GCD
(a)
∠CGH
= 180° - 41° - 47°
= 92° (Angles sum of triangle)
∠CGD
= 180° - 92°
= 88° (Angles on a straight line)
(b)
∠FDE
= 180° - 111° - 32°
= 37° (Angles sum of triangle)
∠CDG = ∠FDE = 37° (Vertically opposite angles)
∠GCD
= 180° - 88° - 37°
= 55° (Angles sum of triangle)
Answer(s): (a) 88°; (b) 55°
