In the figure, EFH and KJlG are straight lines. ∠EKJ = 41°, ∠KEJ = 47°, ∠FGH = 28° and ∠FHG = 101°. Find
- ∠EJF
- ∠JEF
(a)
∠EJK
= 180° - 47° - 41°
= 92° (Angles sum of triangle)
∠EJF
= 180° - 92°
= 88° (Angles on a straight line)
(b)
∠HFG
= 180° - 101° - 28°
= 51° (Angles sum of triangle)
∠EFJ = ∠HFG = 51° (Vertically opposite angles)
∠JEF
= 180° - 88° - 51°
= 41° (Angles sum of triangle)
Answer(s): (a) 88°; (b) 41°
