In the figure, NPR and TSlQ are straight lines. ∠NTS = 46°, ∠TNS = 42°, ∠PQR = 26° and ∠PRQ = 104°. Find
- ∠NSP
- ∠SNP
(a)
∠NST
= 180° - 42° - 46°
= 92° (Angles sum of triangle)
∠NSP
= 180° - 92°
= 88° (Angles on a straight line)
(b)
∠RPQ
= 180° - 104° - 26°
= 50° (Angles sum of triangle)
∠NPS = ∠RPQ = 50° (Vertically opposite angles)
∠SNP
= 180° - 88° - 50°
= 42° (Angles sum of triangle)
Answer(s): (a) 88°; (b) 42°
