In the figure, NPR and TSlQ are straight lines. ∠NTS = 40°, ∠TNS = 46°, ∠PQR = 33° and ∠PRQ = 119°. Find
- ∠NSP
- ∠SNP
(a)
∠NST
= 180° - 46° - 40°
= 94° (Angles sum of triangle)
∠NSP
= 180° - 94°
= 86° (Angles on a straight line)
(b)
∠RPQ
= 180° - 119° - 33°
= 28° (Angles sum of triangle)
∠NPS = ∠RPQ = 28° (Vertically opposite angles)
∠SNP
= 180° - 86° - 28°
= 66° (Angles sum of triangle)
Answer(s): (a) 86°; (b) 66°