In the figure, JKM and PNlL are straight lines. ∠JPN = 43°, ∠PJN = 41°, ∠KLM = 28° and ∠KML = 100°. Find
- ∠JNK
- ∠NJK
(a)
∠JNP
= 180° - 41° - 43°
= 96° (Angles sum of triangle)
∠JNK
= 180° - 96°
= 84° (Angles on a straight line)
(b)
∠MKL
= 180° - 100° - 28°
= 52° (Angles sum of triangle)
∠JKN = ∠MKL = 52° (Vertically opposite angles)
∠NJK
= 180° - 84° - 52°
= 44° (Angles sum of triangle)
Answer(s): (a) 84°; (b) 44°