In the figure, ABD and FElC are straight lines. ∠AFE = 47°, ∠FAE = 49°, ∠BCD = 31° and ∠BDC = 118°. Find
- ∠AEB
- ∠EAB
(a)
∠AEF
= 180° - 49° - 47°
= 84° (Angles sum of triangle)
∠AEB
= 180° - 84°
= 96° (Angles on a straight line)
(b)
∠DBC
= 180° - 118° - 31°
= 31° (Angles sum of triangle)
∠ABE = ∠DBC = 31° (Vertically opposite angles)
∠EAB
= 180° - 96° - 31°
= 53° (Angles sum of triangle)
Answer(s): (a) 96°; (b) 53°
