In the figure, FGJ and LKlH are straight lines. ∠FLK = 45°, ∠LFK = 43°, ∠GHJ = 38° and ∠GJH = 120°. Find
- ∠FKG
- ∠KFG
(a)
∠FKL
= 180° - 43° - 45°
= 92° (Angles sum of triangle)
∠FKG
= 180° - 92°
= 88° (Angles on a straight line)
(b)
∠JGH
= 180° - 120° - 38°
= 22° (Angles sum of triangle)
∠FGK = ∠JGH = 22° (Vertically opposite angles)
∠KFG
= 180° - 88° - 22°
= 70° (Angles sum of triangle)
Answer(s): (a) 88°; (b) 70°
