In the figure, BCE and GFlD are straight lines. ∠BGF = 40°, ∠GBF = 40°, ∠CDE = 32° and ∠CED = 104°. Find
- ∠BFC
- ∠FBC
(a)
∠BFG
= 180° - 40° - 40°
= 100° (Angles sum of triangle)
∠BFC
= 180° - 100°
= 80° (Angles on a straight line)
(b)
∠ECD
= 180° - 104° - 32°
= 44° (Angles sum of triangle)
∠BCF = ∠ECD = 44° (Vertically opposite angles)
∠FBC
= 180° - 80° - 44°
= 56° (Angles sum of triangle)
Answer(s): (a) 80°; (b) 56°
