In the figure, KLN and QPlM are straight lines. ∠KQP = 50°, ∠QKP = 42°, ∠LMN = 26° and ∠LNM = 116°. Find
- ∠KPL
- ∠PKL
(a)
∠KPQ
= 180° - 42° - 50°
= 88° (Angles sum of triangle)
∠KPL
= 180° - 88°
= 92° (Angles on a straight line)
(b)
∠NLM
= 180° - 116° - 26°
= 38° (Angles sum of triangle)
∠KLP = ∠NLM = 38° (Vertically opposite angles)
∠PKL
= 180° - 92° - 38°
= 50° (Angles sum of triangle)
Answer(s): (a) 92°; (b) 50°
