In the figure, UVX and ZYlW are straight lines. ∠UZY = 48°, ∠ZUY = 49°, ∠VWX = 34° and ∠VXW = 105°. Find
- ∠UYV
- ∠YUV
(a)
∠UYZ
= 180° - 49° - 48°
= 83° (Angles sum of triangle)
∠UYV
= 180° - 83°
= 97° (Angles on a straight line)
(b)
∠XVW
= 180° - 105° - 34°
= 41° (Angles sum of triangle)
∠UVY = ∠XVW = 41° (Vertically opposite angles)
∠YUV
= 180° - 97° - 41°
= 42° (Angles sum of triangle)
Answer(s): (a) 97°; (b) 42°
