In the figure, FGJ and LKlH are straight lines. ∠FLK = 50°, ∠LFK = 50°, ∠GHJ = 40° and ∠GJH = 116°. Find
- ∠FKG
- ∠KFG
(a)
∠FKL
= 180° - 50° - 50°
= 80° (Angles sum of triangle)
∠FKG
= 180° - 80°
= 100° (Angles on a straight line)
(b)
∠JGH
= 180° - 116° - 40°
= 24° (Angles sum of triangle)
∠FGK = ∠JGH = 24° (Vertically opposite angles)
∠KFG
= 180° - 100° - 24°
= 56° (Angles sum of triangle)
Answer(s): (a) 100°; (b) 56°
