In the figure, EFH and KJlG are straight lines. ∠EKJ = 42°, ∠KEJ = 40°, ∠FGH = 28° and ∠FHG = 112°. Find
- ∠EJF
- ∠JEF
(a)
∠EJK
= 180° - 40° - 42°
= 98° (Angles sum of triangle)
∠EJF
= 180° - 98°
= 82° (Angles on a straight line)
(b)
∠HFG
= 180° - 112° - 28°
= 40° (Angles sum of triangle)
∠EFJ = ∠HFG = 40° (Vertically opposite angles)
∠JEF
= 180° - 82° - 40°
= 58° (Angles sum of triangle)
Answer(s): (a) 82°; (b) 58°