In the figure, CDF and HGlE are straight lines. ∠CHG = 40°, ∠HCG = 47°, ∠DEF = 26° and ∠DFE = 113°. Find
- ∠CGD
- ∠GCD
(a)
∠CGH
= 180° - 47° - 40°
= 93° (Angles sum of triangle)
∠CGD
= 180° - 93°
= 87° (Angles on a straight line)
(b)
∠FDE
= 180° - 113° - 26°
= 41° (Angles sum of triangle)
∠CDG = ∠FDE = 41° (Vertically opposite angles)
∠GCD
= 180° - 87° - 41°
= 52° (Angles sum of triangle)
Answer(s): (a) 87°; (b) 52°