In the figure, CDF and HGlE are straight lines. ∠CHG = 45°, ∠HCG = 44°, ∠DEF = 32° and ∠DFE = 114°. Find
- ∠CGD
- ∠GCD
(a)
∠CGH
= 180° - 44° - 45°
= 91° (Angles sum of triangle)
∠CGD
= 180° - 91°
= 89° (Angles on a straight line)
(b)
∠FDE
= 180° - 114° - 32°
= 34° (Angles sum of triangle)
∠CDG = ∠FDE = 34° (Vertically opposite angles)
∠GCD
= 180° - 89° - 34°
= 57° (Angles sum of triangle)
Answer(s): (a) 89°; (b) 57°
