In the figure, EFH and KJlG are straight lines. ∠EKJ = 41°, ∠KEJ = 41°, ∠FGH = 36° and ∠FHG = 111°. Find
- ∠EJF
- ∠JEF
(a)
∠EJK
= 180° - 41° - 41°
= 98° (Angles sum of triangle)
∠EJF
= 180° - 98°
= 82° (Angles on a straight line)
(b)
∠HFG
= 180° - 111° - 36°
= 33° (Angles sum of triangle)
∠EFJ = ∠HFG = 33° (Vertically opposite angles)
∠JEF
= 180° - 82° - 33°
= 65° (Angles sum of triangle)
Answer(s): (a) 82°; (b) 65°
