In the figure, UVX and ZYlW are straight lines. ∠UZY = 46°, ∠ZUY = 47°, ∠VWX = 25° and ∠VXW = 119°. Find
- ∠UYV
- ∠YUV
(a)
∠UYZ
= 180° - 47° - 46°
= 87° (Angles sum of triangle)
∠UYV
= 180° - 87°
= 93° (Angles on a straight line)
(b)
∠XVW
= 180° - 119° - 25°
= 36° (Angles sum of triangle)
∠UVY = ∠XVW = 36° (Vertically opposite angles)
∠YUV
= 180° - 93° - 36°
= 51° (Angles sum of triangle)
Answer(s): (a) 93°; (b) 51°
