In the figure, JKM and PNlL are straight lines. ∠JPN = 41°, ∠PJN = 47°, ∠KLM = 33° and ∠KML = 117°. Find
- ∠JNK
- ∠NJK
(a)
∠JNP
= 180° - 47° - 41°
= 92° (Angles sum of triangle)
∠JNK
= 180° - 92°
= 88° (Angles on a straight line)
(b)
∠MKL
= 180° - 117° - 33°
= 30° (Angles sum of triangle)
∠JKN = ∠MKL = 30° (Vertically opposite angles)
∠NJK
= 180° - 88° - 30°
= 62° (Angles sum of triangle)
Answer(s): (a) 88°; (b) 62°
