In the figure, ABD and FElC are straight lines. ∠AFE = 49°, ∠FAE = 41°, ∠BCD = 25° and ∠BDC = 120°. Find
- ∠AEB
- ∠EAB
(a)
∠AEF
= 180° - 41° - 49°
= 90° (Angles sum of triangle)
∠AEB
= 180° - 90°
= 90° (Angles on a straight line)
(b)
∠DBC
= 180° - 120° - 25°
= 35° (Angles sum of triangle)
∠ABE = ∠DBC = 35° (Vertically opposite angles)
∠EAB
= 180° - 90° - 35°
= 55° (Angles sum of triangle)
Answer(s): (a) 90°; (b) 55°
