In the figure, BCD and DEF are isosceles triangles where BD = CD and DE = DF. Given that EG, FJ and BL are straight lines, find
- ∠HML
- ∠FGM
(a)
∠BCD = ∠CBD = ∠DEF = ∠DFE (Isosceles triangle)
∠DFE = ∠GFM = 47° (Verticallly opposite angles)
∠JFM
= 47° - 15°
= 32°
∠FHM
= 180° - 108°
= 72° (Angles on a straight line)
∠HML
= 72° + 32°
= 104° (Exterior angle of a triangle)
(b)
∠FGM
= 104° - 47°
= 57° (Exterior angle of a triangle)
Answer(s): (a) 104°; (b) 57°