In the figure, PQR and RST are isosceles triangles where PR = QR and RS = RT. Given that SU, TW and PY are straight lines, find
- ∠VZY
- ∠TUZ
(a)
∠PQR = ∠QPR = ∠RST = ∠RTS (Isosceles triangle)
∠RTS = ∠UTZ = 39° (Verticallly opposite angles)
∠WTZ
= 39° - 12°
= 27°
∠TVZ
= 180° - 98°
= 82° (Angles on a straight line)
∠VZY
= 82° + 27°
= 109° (Exterior angle of a triangle)
(b)
∠TUZ
= 109° - 39°
= 70° (Exterior angle of a triangle)
Answer(s): (a) 109°; (b) 70°