In the figure, HJK and KLM are isosceles triangles where HK = JK and KL = KM. Given that LN, MQ and HS are straight lines, find
- ∠PTS
- ∠MNT
(a)
∠HJK = ∠JHK = ∠KLM = ∠KML (Isosceles triangle)
∠KML = ∠NMT = 36° (Verticallly opposite angles)
∠QMT
= 36° - 11°
= 25°
∠MPT
= 180° - 99°
= 81° (Angles on a straight line)
∠PTS
= 81° + 25°
= 106° (Exterior angle of a triangle)
(b)
∠MNT
= 106° - 36°
= 70° (Exterior angle of a triangle)
Answer(s): (a) 106°; (b) 70°