In the figure, LMN and NPQ are isosceles triangles where LN = MN and NP = NQ. Given that PR, QT and LV are straight lines, find
- ∠SWV
- ∠QRW
(a)
∠LMN = ∠MLN = ∠NPQ = ∠NQP (Isosceles triangle)
∠NQP = ∠RQW = 46° (Verticallly opposite angles)
∠TQW
= 46° - 11°
= 35°
∠QSW
= 180° - 101°
= 79° (Angles on a straight line)
∠SWV
= 79° + 35°
= 114° (Exterior angle of a triangle)
(b)
∠QRW
= 114° - 46°
= 68° (Exterior angle of a triangle)
Answer(s): (a) 114°; (b) 68°
