In the figure, HJK and KLM are isosceles triangles where HK = JK and KL = KM. Given that LN, MQ and HS are straight lines, find
- ∠PTS
- ∠MNT
(a)
∠HJK = ∠JHK = ∠KLM = ∠KML (Isosceles triangle)
∠KML = ∠NMT = 46° (Verticallly opposite angles)
∠QMT
= 46° - 11°
= 35°
∠MPT
= 180° - 103°
= 77° (Angles on a straight line)
∠PTS
= 77° + 35°
= 112° (Exterior angle of a triangle)
(b)
∠MNT
= 112° - 46°
= 66° (Exterior angle of a triangle)
Answer(s): (a) 112°; (b) 66°