In the figure, PQR and RST are isosceles triangles where PR = QR and RS = RT. Given that SU, TW and PY are straight lines, find
- ∠VZY
- ∠TUZ
(a)
∠PQR = ∠QPR = ∠RST = ∠RTS (Isosceles triangle)
∠RTS = ∠UTZ = 35° (Verticallly opposite angles)
∠WTZ
= 35° - 16°
= 19°
∠TVZ
= 180° - 106°
= 74° (Angles on a straight line)
∠VZY
= 74° + 19°
= 93° (Exterior angle of a triangle)
(b)
∠TUZ
= 93° - 35°
= 58° (Exterior angle of a triangle)
Answer(s): (a) 93°; (b) 58°