In the figure, BCD and DEF are isosceles triangles where BD = CD and DE = DF. Given that EG, FJ and BL are straight lines, find
- ∠HML
- ∠FGM
(a)
∠BCD = ∠CBD = ∠DEF = ∠DFE (Isosceles triangle)
∠DFE = ∠GFM = 40° (Verticallly opposite angles)
∠JFM
= 40° - 12°
= 28°
∠FHM
= 180° - 96°
= 84° (Angles on a straight line)
∠HML
= 84° + 28°
= 112° (Exterior angle of a triangle)
(b)
∠FGM
= 112° - 40°
= 72° (Exterior angle of a triangle)
Answer(s): (a) 112°; (b) 72°