In the figure, MNP and PQR are isosceles triangles where MP = NP and PQ = PR. Given that QS, RU and MW are straight lines, find
- ∠TXW
- ∠RSX
(a)
∠MNP = ∠NMP = ∠PQR = ∠PRQ (Isosceles triangle)
∠PRQ = ∠SRX = 42° (Verticallly opposite angles)
∠URX
= 42° - 15°
= 27°
∠RTX
= 180° - 103°
= 77° (Angles on a straight line)
∠TXW
= 77° + 27°
= 104° (Exterior angle of a triangle)
(b)
∠RSX
= 104° - 42°
= 62° (Exterior angle of a triangle)
Answer(s): (a) 104°; (b) 62°