In the figure, MNP and PQR are isosceles triangles where MP = NP and PQ = PR. Given that QS, RU and MW are straight lines, find
- ∠TXW
- ∠RSX
(a)
∠MNP = ∠NMP = ∠PQR = ∠PRQ (Isosceles triangle)
∠PRQ = ∠SRX = 44° (Verticallly opposite angles)
∠URX
= 44° - 16°
= 28°
∠RTX
= 180° - 96°
= 84° (Angles on a straight line)
∠TXW
= 84° + 28°
= 112° (Exterior angle of a triangle)
(b)
∠RSX
= 112° - 44°
= 68° (Exterior angle of a triangle)
Answer(s): (a) 112°; (b) 68°