In the figure, LMN and NPQ are isosceles triangles where LN = MN and NP = NQ. Given that PR, QT and LV are straight lines, find
- ∠SWV
- ∠QRW
(a)
∠LMN = ∠MLN = ∠NPQ = ∠NQP (Isosceles triangle)
∠NQP = ∠RQW = 35° (Verticallly opposite angles)
∠TQW
= 35° - 16°
= 19°
∠QSW
= 180° - 108°
= 72° (Angles on a straight line)
∠SWV
= 72° + 19°
= 91° (Exterior angle of a triangle)
(b)
∠QRW
= 91° - 35°
= 56° (Exterior angle of a triangle)
Answer(s): (a) 91°; (b) 56°