In the figure, LMN and NPQ are isosceles triangles where LN = MN and NP = NQ. Given that PR, QT and LV are straight lines, find
- ∠SWV
- ∠QRW
(a)
∠LMN = ∠MLN = ∠NPQ = ∠NQP (Isosceles triangle)
∠NQP = ∠RQW = 39° (Verticallly opposite angles)
∠TQW
= 39° - 11°
= 28°
∠QSW
= 180° - 106°
= 74° (Angles on a straight line)
∠SWV
= 74° + 28°
= 102° (Exterior angle of a triangle)
(b)
∠QRW
= 102° - 39°
= 63° (Exterior angle of a triangle)
Answer(s): (a) 102°; (b) 63°