In the figure, MNP and PQR are isosceles triangles where MP = NP and PQ = PR. Given that QS, RU and MW are straight lines, find
- ∠TXW
- ∠RSX
(a)
∠MNP = ∠NMP = ∠PQR = ∠PRQ (Isosceles triangle)
∠PRQ = ∠SRX = 46° (Verticallly opposite angles)
∠URX
= 46° - 16°
= 30°
∠RTX
= 180° - 106°
= 74° (Angles on a straight line)
∠TXW
= 74° + 30°
= 104° (Exterior angle of a triangle)
(b)
∠RSX
= 104° - 46°
= 58° (Exterior angle of a triangle)
Answer(s): (a) 104°; (b) 58°