In the figure, PQR and RST are isosceles triangles where PR = QR and RS = RT. Given that SU, TW and PY are straight lines, find
- ∠VZY
- ∠TUZ
(a)
∠PQR = ∠QPR = ∠RST = ∠RTS (Isosceles triangle)
∠RTS = ∠UTZ = 41° (Verticallly opposite angles)
∠WTZ
= 41° - 14°
= 27°
∠TVZ
= 180° - 100°
= 80° (Angles on a straight line)
∠VZY
= 80° + 27°
= 107° (Exterior angle of a triangle)
(b)
∠TUZ
= 107° - 41°
= 66° (Exterior angle of a triangle)
Answer(s): (a) 107°; (b) 66°