In the figure, HJK and KLM are isosceles triangles where HK = JK and KL = KM. Given that LN, MQ and HS are straight lines, find
- ∠PTS
- ∠MNT
(a)
∠HJK = ∠JHK = ∠KLM = ∠KML (Isosceles triangle)
∠KML = ∠NMT = 35° (Verticallly opposite angles)
∠QMT
= 35° - 16°
= 19°
∠MPT
= 180° - 105°
= 75° (Angles on a straight line)
∠PTS
= 75° + 19°
= 94° (Exterior angle of a triangle)
(b)
∠MNT
= 94° - 35°
= 59° (Exterior angle of a triangle)
Answer(s): (a) 94°; (b) 59°
