In the figure, MNP and PQR are isosceles triangles where MP = NP and PQ = PR. Given that QS, RU and MW are straight lines, find
- ∠TXW
- ∠RSX
(a)
∠MNP = ∠NMP = ∠PQR = ∠PRQ (Isosceles triangle)
∠PRQ = ∠SRX = 47° (Verticallly opposite angles)
∠URX
= 47° - 13°
= 34°
∠RTX
= 180° - 108°
= 72° (Angles on a straight line)
∠TXW
= 72° + 34°
= 106° (Exterior angle of a triangle)
(b)
∠RSX
= 106° - 47°
= 59° (Exterior angle of a triangle)
Answer(s): (a) 106°; (b) 59°