In the figure, HJK and KLM are isosceles triangles where HK = JK and KL = KM. Given that LN, MQ and HS are straight lines, find
- ∠PTS
- ∠MNT
(a)
∠HJK = ∠JHK = ∠KLM = ∠KML (Isosceles triangle)
∠KML = ∠NMT = 40° (Verticallly opposite angles)
∠QMT
= 40° - 14°
= 26°
∠MPT
= 180° - 106°
= 74° (Angles on a straight line)
∠PTS
= 74° + 26°
= 100° (Exterior angle of a triangle)
(b)
∠MNT
= 100° - 40°
= 60° (Exterior angle of a triangle)
Answer(s): (a) 100°; (b) 60°