In the figure, MNP and PQR are isosceles triangles where MP = NP and PQ = PR. Given that QS, RU and MW are straight lines, find
- ∠TXW
- ∠RSX
(a)
∠MNP = ∠NMP = ∠PQR = ∠PRQ (Isosceles triangle)
∠PRQ = ∠SRX = 39° (Verticallly opposite angles)
∠URX
= 39° - 16°
= 23°
∠RTX
= 180° - 104°
= 76° (Angles on a straight line)
∠TXW
= 76° + 23°
= 99° (Exterior angle of a triangle)
(b)
∠RSX
= 99° - 39°
= 60° (Exterior angle of a triangle)
Answer(s): (a) 99°; (b) 60°
