In the figure, BCD and DEF are isosceles triangles where BD = CD and DE = DF. Given that EG, FJ and BL are straight lines, find
- ∠HML
- ∠FGM
(a)
∠BCD = ∠CBD = ∠DEF = ∠DFE (Isosceles triangle)
∠DFE = ∠GFM = 42° (Verticallly opposite angles)
∠JFM
= 42° - 15°
= 27°
∠FHM
= 180° - 97°
= 83° (Angles on a straight line)
∠HML
= 83° + 27°
= 110° (Exterior angle of a triangle)
(b)
∠FGM
= 110° - 42°
= 68° (Exterior angle of a triangle)
Answer(s): (a) 110°; (b) 68°