In the figure, LMN and NPQ are isosceles triangles where LN = MN and NP = NQ. Given that PR, QT and LV are straight lines, find
- ∠SWV
- ∠QRW
(a)
∠LMN = ∠MLN = ∠NPQ = ∠NQP (Isosceles triangle)
∠NQP = ∠RQW = 43° (Verticallly opposite angles)
∠TQW
= 43° - 13°
= 30°
∠QSW
= 180° - 109°
= 71° (Angles on a straight line)
∠SWV
= 71° + 30°
= 101° (Exterior angle of a triangle)
(b)
∠QRW
= 101° - 43°
= 58° (Exterior angle of a triangle)
Answer(s): (a) 101°; (b) 58°