In the figure, BCD and DEF are isosceles triangles where BD = CD and DE = DF. Given that EG, FJ and BL are straight lines, find
- ∠HML
- ∠FGM
(a)
∠BCD = ∠CBD = ∠DEF = ∠DFE (Isosceles triangle)
∠DFE = ∠GFM = 44° (Verticallly opposite angles)
∠JFM
= 44° - 10°
= 34°
∠FHM
= 180° - 107°
= 73° (Angles on a straight line)
∠HML
= 73° + 34°
= 107° (Exterior angle of a triangle)
(b)
∠FGM
= 107° - 44°
= 63° (Exterior angle of a triangle)
Answer(s): (a) 107°; (b) 63°