In the figure, PQR and RST are isosceles triangles where PR = QR and RS = RT. Given that SU, TW and PY are straight lines, find
- ∠VZY
- ∠TUZ
(a)
∠PQR = ∠QPR = ∠RST = ∠RTS (Isosceles triangle)
∠RTS = ∠UTZ = 45° (Verticallly opposite angles)
∠WTZ
= 45° - 14°
= 31°
∠TVZ
= 180° - 96°
= 84° (Angles on a straight line)
∠VZY
= 84° + 31°
= 115° (Exterior angle of a triangle)
(b)
∠TUZ
= 115° - 45°
= 70° (Exterior angle of a triangle)
Answer(s): (a) 115°; (b) 70°