In the figure, EFG and GHJ are isosceles triangles where EG = FG and GH = GJ. Given that HK, JM and EP are straight lines, find
- ∠LQP
- ∠JKQ
(a)
∠EFG = ∠FEG = ∠GHJ = ∠GJH (Isosceles triangle)
∠GJH = ∠KJQ = 44° (Verticallly opposite angles)
∠MJQ
= 44° - 10°
= 34°
∠JLQ
= 180° - 96°
= 84° (Angles on a straight line)
∠LQP
= 84° + 34°
= 118° (Exterior angle of a triangle)
(b)
∠JKQ
= 118° - 44°
= 74° (Exterior angle of a triangle)
Answer(s): (a) 118°; (b) 74°