In the figure, HJK and KLM are isosceles triangles where HK = JK and KL = KM. Given that LN, MQ and HS are straight lines, find
- ∠PTS
- ∠MNT
(a)
∠HJK = ∠JHK = ∠KLM = ∠KML (Isosceles triangle)
∠KML = ∠NMT = 44° (Verticallly opposite angles)
∠QMT
= 44° - 11°
= 33°
∠MPT
= 180° - 106°
= 74° (Angles on a straight line)
∠PTS
= 74° + 33°
= 107° (Exterior angle of a triangle)
(b)
∠MNT
= 107° - 44°
= 63° (Exterior angle of a triangle)
Answer(s): (a) 107°; (b) 63°