In the figure, PQR and RST are isosceles triangles where PR = QR and RS = RT. Given that SU, TW and PY are straight lines, find
- ∠VZY
- ∠TUZ
(a)
∠PQR = ∠QPR = ∠RST = ∠RTS (Isosceles triangle)
∠RTS = ∠UTZ = 38° (Verticallly opposite angles)
∠WTZ
= 38° - 15°
= 23°
∠TVZ
= 180° - 103°
= 77° (Angles on a straight line)
∠VZY
= 77° + 23°
= 100° (Exterior angle of a triangle)
(b)
∠TUZ
= 100° - 38°
= 62° (Exterior angle of a triangle)
Answer(s): (a) 100°; (b) 62°