In the figure, BCD and DEF are isosceles triangles where BD = CD and DE = DF. Given that EG, FJ and BL are straight lines, find
- ∠HML
- ∠FGM
(a)
∠BCD = ∠CBD = ∠DEF = ∠DFE (Isosceles triangle)
∠DFE = ∠GFM = 45° (Verticallly opposite angles)
∠JFM
= 45° - 12°
= 33°
∠FHM
= 180° - 95°
= 85° (Angles on a straight line)
∠HML
= 85° + 33°
= 118° (Exterior angle of a triangle)
(b)
∠FGM
= 118° - 45°
= 73° (Exterior angle of a triangle)
Answer(s): (a) 118°; (b) 73°