In the figure, LMN and NPQ are isosceles triangles where LN = MN and NP = NQ. Given that PR, QT and LV are straight lines, find
- ∠SWV
- ∠QRW
(a)
∠LMN = ∠MLN = ∠NPQ = ∠NQP (Isosceles triangle)
∠NQP = ∠RQW = 36° (Verticallly opposite angles)
∠TQW
= 36° - 14°
= 22°
∠QSW
= 180° - 104°
= 76° (Angles on a straight line)
∠SWV
= 76° + 22°
= 98° (Exterior angle of a triangle)
(b)
∠QRW
= 98° - 36°
= 62° (Exterior angle of a triangle)
Answer(s): (a) 98°; (b) 62°