In the figure, GHJ and JKL are isosceles triangles where GJ = HJ and JK = JL. Given that KM, LP and GR are straight lines, find
- ∠NSR
- ∠LMS
(a)
∠GHJ = ∠HGJ = ∠JKL = ∠JLK (Isosceles triangle)
∠JLK = ∠MLS = 44° (Verticallly opposite angles)
∠PLS
= 44° - 11°
= 33°
∠LNS
= 180° - 108°
= 72° (Angles on a straight line)
∠NSR
= 72° + 33°
= 105° (Exterior angle of a triangle)
(b)
∠LMS
= 105° - 44°
= 61° (Exterior angle of a triangle)
Answer(s): (a) 105°; (b) 61°
