In the figure, HJK and KLM are isosceles triangles where HK = JK and KL = KM. Given that LN, MQ and HS are straight lines, find
- ∠PTS
- ∠MNT
(a)
∠HJK = ∠JHK = ∠KLM = ∠KML (Isosceles triangle)
∠KML = ∠NMT = 37° (Verticallly opposite angles)
∠QMT
= 37° - 13°
= 24°
∠MPT
= 180° - 99°
= 81° (Angles on a straight line)
∠PTS
= 81° + 24°
= 105° (Exterior angle of a triangle)
(b)
∠MNT
= 105° - 37°
= 68° (Exterior angle of a triangle)
Answer(s): (a) 105°; (b) 68°